(x/x^2-4)+(1/x+2)=3

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Solution for (x/x^2-4)+(1/x+2)=3 equation: 


D( x )

x = 0

x^2 = 0

x = 0

x = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

x/(x^2)+1/x-4+2 = 3 // - 3

x/(x^2)+1/x-4-3+2 = 0

2*x^-1 = 5 // : 2

x^-1 = 5/2

-1 < 0

1/(x^1) = 5/2 // * x^1

1 = 5/2*x^1 // : 5/2

2/5 = x^1

x = 2/5

x = 2/5

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